3[9(x+4)+2(x+1)]=0

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Solution for 3[9(x+4)+2(x+1)]=0 equation:


Simplifying
3[9(x + 4) + 2(x + 1)] = 0

Reorder the terms:
3[9(4 + x) + 2(x + 1)] = 0
3[(4 * 9 + x * 9) + 2(x + 1)] = 0
3[(36 + 9x) + 2(x + 1)] = 0

Reorder the terms:
3[36 + 9x + 2(1 + x)] = 0
3[36 + 9x + (1 * 2 + x * 2)] = 0
3[36 + 9x + (2 + 2x)] = 0

Reorder the terms:
3[36 + 2 + 9x + 2x] = 0

Combine like terms: 36 + 2 = 38
3[38 + 9x + 2x] = 0

Combine like terms: 9x + 2x = 11x
3[38 + 11x] = 0
[38 * 3 + 11x * 3] = 0
[114 + 33x] = 0

Solving
114 + 33x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-114' to each side of the equation.
114 + -114 + 33x = 0 + -114

Combine like terms: 114 + -114 = 0
0 + 33x = 0 + -114
33x = 0 + -114

Combine like terms: 0 + -114 = -114
33x = -114

Divide each side by '33'.
x = -3.454545455

Simplifying
x = -3.454545455

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